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6g^2-5g-5=0
a = 6; b = -5; c = -5;
Δ = b2-4ac
Δ = -52-4·6·(-5)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{145}}{2*6}=\frac{5-\sqrt{145}}{12} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{145}}{2*6}=\frac{5+\sqrt{145}}{12} $
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